在Turbo C ++中将字符串分配给结构中的char数组

Question

I should mention that I am on Turbo C++ (yes the old one) because it is required by my school. 我应该提到我正在使用Turbo C ++（是旧版本），因为我的学校要求这样做。

I have a structure like this: 我有这样的结构：

struct move{
 int power;
 int pp;
 char name[10];
 };

When I try to make a new variable if I do this: 当我尝试执行以下操作创建新变量时：

move tackle;
tackle.pp = 10;
tackle.power = 20;
tackle.name = "tackle";

I get an error as: 我收到如下错误：

Error NONAME00.CPP 11: Lvalue required

But this works: 但这有效：

move tackle = {20, 10, "tackle"}

it works. 有用。

What am I doing wrong? 我究竟做错了什么？

PS line 11 is the tackle.name = "tackle" , sorry if I was unclear earlier. PS第11行是tackle.name = "tackle" ，如果我之前不清楚，抱歉。

Answer 1

You can't assign to an array, but you can initialise it. 您不能分配给数组，但可以对其进行初始化。

tackle.name = "tackle";

is an assignment, while 是一项任务，而

move tackle = {20, 10, "tackle"};

is an initialisation. 是一个初始化。

To replace the contents of the array, use strcpy : 要替换数组的内容，请使用strcpy ：

strcpy(tackle.name, "tackle");

or, better, use string if you're allowed to: 或者，如果允许，请使用string ：

#include <string>

struct move{
 int power;
 int pp;
 string name;
 };

Answer 2

您正在使用c风格的字符串，应通过以下方式对其进行初始化

strcpy(tackle.name, "tackle");

Answer 3

This line 这条线

tackle.name = "tackle";

tries to assign one array to another which not a supported operation in C or C++. 尝试将一个数组分配给C或C ++中不支持的操作的另一个数组。

However initialization like char name[10] = "tackle" is fine by the standard and is supported. 但是，标准支持并支持像char name[10] = "tackle"这样的初始化。