将awk放入函数中

Question

I have 4 awks that are really similiar so I want to put them in a function. My awk code is...

awk -v MYPATH="$MYPATH" -v FILE_EXT="$FILE_EXT" -v NAME_OF_FILE="$NAME_OF_FILE" -v DATE="$DATE" -v pattern="$STORED_PROCS_BEGIN" '
        $0 ~ pattern {
            rec = $1 OFS $2 OFS $4 OFS $7
            for (i=9; i<=NF; i++) {
                rec = rec OFS $i
                if ($i ~ /\([01]\)/) {
                    break
                }
            }
            print rec >> "'$MYPATH''$NAME_OF_FILE''$DATE'.'$FILE_EXT'"
        }
    ' "$FILE_LOCATION"

So the pattern and regular expression differ. How can I put this awk in a function where I can replace pattern with $1 and /([01])/ with $2 if I already use those in my awk?

EDIT: I was thinking I can do...

 printFmt(){
   awk -v .......
     $0 ~ patten {
        rec..
        for..
           rec..
           if($i ~ search) 
              break
 print rec

then call with printFmt set?

    }

Answer 1

Not sure where the problem is since you already have in your code exactly what you need to do but maybe this will help by simplifying it a bit:

$ cat tst.sh
function prtStuff() {
    awk -v x="$1" 'BEGIN{ print x }'
}

prtStuff "foo"
prtStuff "---"
prtStuff "bar"

$ ./tst.sh
foo
---
bar