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将十进制或Varchar转换为日期

[英]Convert Decimal or Varchar into Date

I have 2 fields. 我有2个领域。

Birth= Datatype Decimal(12,4) & Date = Datatype Date 出生=数据类型十进制(12,4)&日期=数据类型日期

Birth         Date 
19650101   2015-07-09  

how do i get a result that looks like this 我如何获得看起来像这样的结果

i want the result to be like this 我希望结果像这样

Birth             Date          
1965-01-01       2015-07-09       

where the Birth is a Date datatype and not a decimal (12,4) 其中Birth是Date数据类型而不是十进制(12,4)

To convert the number 19650101 to a date use 要将数字19650101转换为日期,请使用

CONVERT(DATETIME, CAST(Birth AS VARCHAR(8)), 112)

To get the number of years (to one decimal) you could do: 要获得年数(至小数点后一位),您可以执行以下操作:

ROUND(
    DATEDIFF(day,
         CONVERT(DATETIME, CAST(Birth AS VARCHAR(8)), 112),
         [Date])/365.25
     ,1)

Which won't be exact but should be close enough to tenths of a year. 可能不确切,但应接近一年的十分之一。

You can use this: 您可以使用此:

-- Create demo data
CREATE TABLE #dates(birth int, date date)

INSERT INTO #dates(birth,date)
VALUES(19650101,N'2015-07-09')

-- Your work
SELECT CONVERT(date,CONVERT(nvarchar(max),birth),112) as birth, date, 
        DATEDIFF(year,
            CONVERT(date,CONVERT(nvarchar(max),birth),112),
            date
        ) as years
FROM #dates

-- Cleanup
DROP TABLE #dates

This depends on the exact format you provides ( 19650101 ). 这取决于您提供的确切格式( 19650101 )。

I think you don't need to round. 我认为您不需要四舍五入。 Just convert your decimal value and put "-" like below : ) 只需将您的十进制值转换为“-”,如下所示:)

select left(birth,4) +'-' + 
substring(convert(nvarchar,birth),5,2)+'-'+ 
substring(convert(nvarchar,birth),7,2)

这是进行此转换的一种方法。

cast(cast(FLOOR(birth) as CHAR(8)) as DATE)

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