IntelliSense：不存在从“ std :: string”到“ char”的合适转换函数，那么我该如何处理？

Question

the char letters[] = {value}; part is where i am getting the problem

 static string Cipher(string value, int offset)
  { 
char letters[] = {value};
char DifferentLetters[] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','u','r','s','t','v','w','x','y','z'};


for (int i = 0; i < DifferentLetters[i]; i++)
{
    char letter = DifferentLetters[i];

    int defaultOffset = offset;

    if(letter > 'z')
    {
        letter = (char)(letter - defaultOffset);
    }
    else if(letter < 'a')

Answer 1

Setting aside the more basic question of why you would want to do such a thing, the equivalent to what you expect

char letters[] = {value};

to mean would be

char letters[value.size()+1];
memcpy(letters,value.c_str(),value.size()+1);

Of course, that assumes a newer version of C++ that allows run time sizing of local C arrays (I forget which version that was added in, but certainly not very early versions). Also you need to include something like string.h to get the declaraction of memcpy.

The following might be a cleaner alternative, but it is further from the original meaning in ways that may cause it to be unacceptable (depending on subsequent use of letters and value):

char* letters = value.c_str();