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日期格式转换

[英]date format conversion am to date

I need a help on how to convert '09-07-15 07:41:01AM' to '2015-07-09 07:41:01'. 我需要有关如何将“ '09-07-15 07:41:01AM'转换为'2015-07-09 07:41:01'.

I have tried below query but it is not giving accurate result. 我已经在下面的查询中尝试过,但是没有给出准确的结果。

select to_char(to_date('09-07-15 07:41:01AM'
,'DD-MM-YYYY HH:MI:SS AM')
,'YYYY-MM-DD HH24:MI:SS') from dual

Have you tried 你有没有尝试过

select to_char(add_months(to_date('09-07-15 07:41:01AM','DD-MM-YY HH:MI:SS AM'),24000),'YYYY-MM-DD HH24:MI:SS') from dual

It looks like you have to many Y's, and your M's ans D's are inconsistent! 看来您必须有很多Y,而您的M和D却不一致!

I'm not sure if it should be YY-MM-DD or YY-mm-dd ? 我不确定是YY-MM-DD还是YY-mm-dd

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