[英]date format conversion am to date
I need a help on how to convert '09-07-15 07:41:01AM'
to '2015-07-09 07:41:01'.
我需要有关如何将“
'09-07-15 07:41:01AM'
转换为'2015-07-09 07:41:01'.
I have tried below query but it is not giving accurate result. 我已经在下面的查询中尝试过,但是没有给出准确的结果。
select to_char(to_date('09-07-15 07:41:01AM'
,'DD-MM-YYYY HH:MI:SS AM')
,'YYYY-MM-DD HH24:MI:SS') from dual
Have you tried 你有没有尝试过
select to_char(add_months(to_date('09-07-15 07:41:01AM','DD-MM-YY HH:MI:SS AM'),24000),'YYYY-MM-DD HH24:MI:SS') from dual
It looks like you have to many Y's, and your M's ans D's are inconsistent! 看来您必须有很多Y,而您的M和D却不一致!
I'm not sure if it should be YY-MM-DD
or YY-mm-dd
? 我不确定是
YY-MM-DD
还是YY-mm-dd
?
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