根据另一个布尔列表从一个列表中获取元素

Question

I have two lists of the same size, one is a list of strings, and the other a list of booleans ( True , False ) and I want to return a list of strings only if the index is True.

b_list = [True, False, True]
s_list = ['abc', 'sfsfsfsf', 'def']

want

s_list = ['abc','def'] 

Answer 1

Use itertools.compress

compress(data, selectors) : Return data elements corresponding to true selectors elements

So s_list is data and b_list is selectors :

In [8]: import itertools

In [9]: list(itertools.compress(s_list, b_list))
Out[9]: ['abc', 'def']

Answer 2

如果没有使用列表理解的itertools ：

[y for (x,y) in zip(b_list, s_list) if x]