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使用 DOMDocument PHP 获取 Xpath 父节点?

[英]Get Xpath parent node with DOMDocument PHP?

I need to get the parent of a particular node in php.我需要在 php 中获取特定节点的父节点。 I'm using DOMDocument and XPath.我正在使用 DOMDocument 和 XPath。 My XML is this:我的 XML 是这样的:

<ProdCategories>
<ProdCategory>

    <Id>138</Id>

    <Name>Parent Category</Name>

    <SubCategories>

        <ProdCategory>

            <Id>141</Id>

            <Name>Category child</Name>

        </ProdCategory>
   </SubCategories>
</ProdCategory>
</ProdCategories>

The php code: php代码:

$dom = new DOMDocument();
$dom->load("ProdCategories_small.xml");
$xpath = new DOMXPath($dom);
$nodes = $xpath->query('//ProdCategory/Id[.="141"]/parent::*')->item(0);
print_r($nodes); 

The print is:印刷品是:

 DOMElement Object ( [tagName] => ProdCategory [schemaTypeInfo] => [nodeName] => ProdCategory [nodeValue] => 141 Category child [nodeType] => 1 [parentNode] => (object value omitted) [childNodes] => (object value omitted) [firstChild] => (object value omitted) [lastChild] => (object value omitted) [previousSibling] => (object value omitted)

The [parentNode] is (object value omitted) , why? [parentNode] is (object value omitted) ,为什么? I would get我会得到

    <Id>138</Id>

    <Name>Parent Category</Name>`

The [parentNode] is (object value omitted) , why? [parentNode] is (object value omitted) ,为什么?

This is because you use the print_r function and it creates such an output ( via an internal helper function of the dom extension ).这是因为您使用了print_r函数并且它创建了这样的输出(通过 dom 扩展的内部辅助函数)。 The line in code which is creating this is:创建此代码的代码行是:

print_r($nodes);

The string " (object value omitted) " is given by the DOMNode when either print_r or var_dump are used on it.当使用print_rvar_dump时,字符串“ (object value omitted) ”由DOMNode给出。 It tells you, that the object value of that field (named parentNode ) is not displayed but omitted.它告诉您,该字段(名为parentNode )的对象没有显示而是省略了。

From that message you could conclude that the field has a value that is an object.从该消息中,您可以得出结论,该字段的值是一个对象。 A simple check for the class-name could verify this:对类名的简单检查可以验证这一点:

echo get_class($nodes->parentNode), "\n"; # outputs  "DOMElement"

Compare that with fields which are an integer or an (empty) string:将其与整数或(空)字符串的字段进行比较:

[nodeType] => 1
...
[prefix] => 
[localName] => ProdCategory

So I hope this clears it up for you.所以我希望这能让你明白。 Just access the field to get the parent node object:只需访问该字段即可获取父节点对象:

$parent = $nodes->parentNode;

and done.并做了。

If you wonder about a certain string that PHP gives you and you have the feeling it might be something internal, you can quickly search all of PHP's codebase on http://lxr.php.net/ , here is an example query for the string in your question .如果你想知道 PHP 给你的某个字符串,并且你觉得它可能是内部的东西,你可以在http://lxr.php.net/上快速搜索所有 PHP 的代码库, 这里是一个字符串查询示例在你的问题中

Just treat the xpath query nodes as filesystem paths, as mentioned here只是把XPath查询节点作为文件系统路径,提到这里

Move up 2 nodes and get the parent and get what you need from it, such as the Id or Name.向上移动 2 个节点并获取父节点并从中获取您需要的内容,例如 Id 或 Name。

Example:例子:

<?php

$dom = new DOMDocument();
$dom->load("ProdCategories_small.xml");
$xpath = new DOMXPath($dom);

$parentNode = $xpath->query('//ProdCategory[Id="141"]/../..')->item(0);

$id = $xpath->query('./Id', $parentNode)->item(0);
$name = $xpath->query('./Name',$parentNode)->item(0);

print "Id: " . $id->nodeValue . PHP_EOL;
print "Name: " . $name->nodeValue . PHP_EOL;

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