[英]create a class Table for an inexisting table slick scala (Slick 3.0.0, scala)
Assume that we have a database which contains two tables: Coffee
and Suppliers
and we have their corresponding case classes and tables, just as in the documentation: 假设我们有一个数据库,其中包含两个表: Coffee
和Suppliers
,并且具有相应的案例类和表,就像在文档中一样:
import scala.slick.driver.MySQLDriver.simple._
import scala.slick.lifted.{ProvenShape, ForeignKeyQuery}
// A Suppliers table with 6 columns: id, name, street, city, state, zip
class Suppliers(tag: Tag) extends Table[(Int, String, String, String, String, String)](tag, "SUPPLIERS") {
def id: Column[Int] = column[Int]("SUP_ID", O.PrimaryKey) // This is the primary key column
def name: Column[String] = column[String]("SUP_NAME")
def street: Column[String] = column[String]("STREET")
def city: Column[String] = column[String]("CITY")
def state: Column[String] = column[String]("STATE")
def zip: Column[String] = column[String]("ZIP")
// Every table needs a * projection with the same type as the table's type parameter
def * : ProvenShape[(Int, String, String, String, String, String)] = (id, name, street, city, state, zip)
}
// A Coffees table with 5 columns: name, supplier id, price, sales, total
class Coffees(tag: Tag) extends Table[(String, Int, Double, Int, Int)](tag, "COFFEES") {
def name: Column[String] = column[String]("COF_NAME", O.PrimaryKey)
def supID: Column[Int] = column[Int]("SUP_ID")
def price: Column[Double] = column[Double]("PRICE")
def sales: Column[Int] = column[Int]("SALES")
def total: Column[Int] = column[Int]("TOTAL")
def * : ProvenShape[(String, Int, Double, Int, Int)] = (name, supID, price, sales, total)
// A reified foreign key relation that can be navigated to create a join
def supplier: ForeignKeyQuery[Suppliers, (Int, String, String, String, String, String)] =
foreignKey("SUP_FK", supID, TableQuery[Suppliers])(_.id)
}
Now assume that we want to do a join: 现在假设我们要进行联接:
val result = for {
c <- coffees
s <- suppliers if c.supID === s.id
} yield (c.name, s.name)
And here dealing with the result is complicated ( and it's more complicated if we have a lot of joins) because we need always to remember the order of names, to know what _._1
or _._2
refer to ... etc. 在这里处理结果很复杂(如果有很多联接,它也会更复杂),因为我们需要始终记住名称的顺序,知道_._1
或_._2
引用...等。
Question 1 Is there a way to change the type of the result as a table of a new class which contains the desired columns ? 问题1是否可以更改结果的类型,使其成为包含所需列的新类的表?
Question 2 Here is a way but I can't finish it, we construct a case class for example: 问题2这是一种方法,但我无法完成,例如,我们构造一个case类:
case class Joined(nameS: String,nameC: String)
and after that we construct the corresponding table which I don't know how 然后我们构造相应的表,我不知道如何
class Joineds extends Table[Joinedclass] {
//Todo
}
and when we write a join we can write something like ( so that we can transform result to a type Joined) : 当我们编写联接时,我们可以写类似的东西(以便我们可以将结果转换为Joined类型):
val result = for {
c <- coffees
s <- suppliers if c.supID === s.id
} yield (c.name, s.name).as(Joinds)
Thank you. 谢谢。
Can you define it like: 您可以像这样定义它吗:
val result = for {
c <- coffees
s <- suppliers if c.supID === s.id
} yield Joined(c.name, s.name)
And the tuck it away in some convenient place? 并把它塞进一些方便的地方?
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