读取文本文件时，如何跳到每行最后一个数字之后的下一行？
[英]How to skip to next line after the last number found in each line when reading a text file?
问题描述
My text file look something like this: 
我的文本文件如下所示：
1 2 3 test//test
4 5 6 dummy//dummy
How can I read this file and only process the numbers present in each line? 如何读取此文件，仅处理每一行中存在的数字？
1 个解决方案
解决方案1
5 已采纳 2015-07-10 10:53:05
Two ways: 两种方式：
By ignoring the rest of the line .
通过忽略其余部分 。 By reading the complete line into a string , put the string in an output string stream , and read only the leading three numbers from the output string stream.
通过将整行读入字符串 ，将字符串放入输出字符串流 ，并仅读取输出字符串流中的前三个数字。
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.
相关问题
从文件读取时如何跳过一行 - How to skip a line when reading from a file
从文件读取时如何使用“ >>”运算符将光标移至下一行 - How to get cursor to next line after using “>>” operator when reading from file
C++：读取文件时如何跳转到下一个立即行？ - C++: How to jump to the next immediate line when reading a file?
读取文件的最后一行 - Reading last line of a file
当我调用另一个 function 读取文本文件中的下几行时，如何使 getline 不跳过文本文件中的一行 - How do I make getline not skip over a line from a text file when I call another function to read the next few lines in a text file
从文件读取时如何跳过数组的第一行？ - How do I skip the first line of an array when reading from a file?
C ++，逐行读取文本文件后得到向量中的错误 - C ++ , getting error in vector , after reading text file line by line
从文件读取下一行 - Reading next line from file
如何在C ++中跳过读取文件中的行？ - How do I skip reading a line in a file in C++?
gnuplot：跳过数据文件的最后/不完整的行 - Gnuplot: skip last/incomplete line of data file
相关标签