在Python中使用Selenium单击具有相同类名的所有元素

Question

I am trying to click on all of the "like" buttons on a webpage. I know how to click on one of them, but I'd like to be able to click them all. They have the same class name, but different id's.

Do I need to create some sort of list and tell it to click on each one of the items on the list? Is there a way to write "click all"?

Here's what my code looks like (I removed the login code):

from selenium import webdriver
from selenium.webdriver.common.keys import Keys

browser = webdriver.Firefox()
browser.set_window_size(650, 700)
browser.get('http://iconosquare.com/viewer.php#/tag/searchterm/grid')

mobile = browser.find_element_by_id('open-menu-mobile')
mobile.click()
search = browser.find_element_by_id('getSearch')
search.click()
search.send_keys('input search term' + Keys.RETURN)

#this gets me to the page I want to click the likes
fitness = browser.find_element_by_css_selector("a[href*='fitness/']")
fitness.click()

#here are the different codes I've tried to use to click all of the "like buttons"

#tried to create a list of all elements with "like" in the id and click on all of them.  It didn't work.
like = browser.find_elements_by_id('like')
for x in range(0,len(like)):
    if like[x].is_displayed():
        like[x].click()

#tried to create a list by class and click on everything within the list and it didn't work.
like = browser.find_elements_by_class_name('like_picto_unselected')
like.click()

AttributeError: 'list' object has no attribute 'click'

I know I can't click on a list because it isn't a single object, but I have no idea how I'd go about this otherwise.

Your help is greatly appreciated.

Answer 1

This is unfortunate, you got two halves of the whole, you cannot find multiple elements by id as ID is unique to a single element.

so combine the iterative method you use with id and the find by elements with classes to get:

like = browser.find_elements_by_class_name('like_picto_unselected')
for x in range(0,len(like)):
    if like[x].is_displayed():
        like[x].click()

I strongly suspect this will work for you. Please tell me if not.