[英]Format Pandas Pivot Table
I met a problem in formatting pivot table that created by Pandas. 我遇到了由Pandas创建的格式化数据透视表的问题。 So I made a matrix table between 2 columns (A,B) from my source data, by using pandas.pivot_table with A as Column, and B as Index.
所以我在源数据的两列(A,B)之间建立了一个矩阵表,使用pandas.pivot_table,A为列,B为索引。
>> df = PD.read_excel("data.xls")
>> table = PD.pivot_table(df,index=["B"],
values='Count',columns=["A"],aggfunc=[NUM.sum],
fill_value=0,margins=True,dropna= True)
>> table
It returns as: 它返回为:
sum
A 1 2 3 All
B
1 23 52 0 75
2 16 35 12 65
3 56 0 0 56
All 95 87 12 196
And I hope to have a format like this: 我希望有这样的格式:
A All_B
1 2 3
1 23 52 0 75
B 2 16 35 12 65
3 56 0 0 56
All_A 95 87 12 196
How should I do this? 我该怎么做? Thanks very much ahead.
非常感谢。
The table returned by pd.pivot_table
is very convenient to do work on (it's single-level index/column) and normally does NOT require any further format manipulation. pd.pivot_table
返回的表非常方便(它的单级索引/列),通常不需要任何进一步的格式操作。 But if you insist on changing the format to the one you mentioned in the post, then you need to construct a multi-level index/column using pd.MultiIndex
. 但是如果你坚持将格式更改为帖子中提到的格式,那么你需要使用
pd.MultiIndex
构建一个多级索引/列。 Here is an example on how to do it. 这是一个如何做到这一点的例子。
Before manipulation, 在操纵之前
import pandas as pd
import numpy as np
np.random.seed(0)
a = np.random.randint(1, 4, 100)
b = np.random.randint(1, 4, 100)
df = pd.DataFrame(dict(A=a,B=b,Val=np.random.randint(1,100,100)))
table = pd.pivot_table(df, index='A', columns='B', values='Val', aggfunc=sum, fill_value=0, margins=True)
print(table)
B 1 2 3 All
A
1 454 649 770 1873
2 628 576 467 1671
3 376 247 481 1104
All 1458 1472 1718 4648
After: 后:
multi_level_column = pd.MultiIndex.from_arrays([['A', 'A', 'A', 'All_B'], [1,2,3,'']])
multi_level_index = pd.MultiIndex.from_arrays([['B', 'B', 'B', 'All_A'], [1,2,3,'']])
table.index = multi_level_index
table.columns = multi_level_column
print(table)
A All_B
1 2 3
B 1 454 649 770 1873
2 628 576 467 1671
3 376 247 481 1104
All_A 1458 1472 1718 4648
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