如何在Django 1.7中的表单模型中获取当前登录的用户ID？

Question

Let's say I have a webpage that displays songs. And let's say there are public and private songs. Public songs are available for everyone to see, while private songs are songs that a certain user has created and are only available for him to see. So the user should only see those songs with the owner_id == NULL and owner_id == currently_logged_in_user_id (his own id)

Model:

import ....

    class Song(models.Model):
        name = models.CharField(max_length=100)    
        duration = models.IntegerField(max_length=15)
        owner = models.ForeignKey(settings.AUTH_USER_MODEL, null=True, blank=True)

        def __unicode__(self):
            return self.name

View:

from django.shortcuts import render, redirect, get_object_or_404
from django.contrib.auth.decorators import login_required
from songapp.models import Song
from songapp.forms import SongInfoForm

@login_required
def song_info(request):
    song = get_object_or_404(Box)
    song_status = song.get_status()
    form = SongInfoForm(initial={'song_list': song.song_list})

    return render(request, 'songapp/song_info.html',
        {'form': form, 'song': song, 'song_status': song_status})

Form:

    from django import forms
    from django.forms import ModelChoiceField

    from songapp.models import Song


    class SongInfoForm(forms.Form):

-->     selected_songs = Song.objects.filter(owner=None) | Song.objects.filter(owner=3)
        song_list = ModelChoiceField(queryset=selected_songs, required=False)

Note the line with the arrow in the Form file. This is where the problem lies. The code works now, but the

(owner = 3)

is hardcoded. I know for a fact that my users id is 3. But I want it to work properly. It should be something like this:

(owner = currently_logged_in_user.id)

I'm still very new to Django and Python and I don't know how to pass the users id to the SongInfoForm FormModel.

Answer 1

I've figured it out.

In views.py change:

form = SongInfoForm(initial={'song_list': song.song_list}, user=request.user)

And thanks to the answers before and this example django form: Passing parameter from view.py to forms gives out error I've came up with this, and it works like a charm.

In forms.py

class SongInfoForm(forms.Form):
    def __init__(self, *args, **kwargs):
        user = kwargs.pop('user')
        super(SongInfoForm, self).__init__(*args, **kwargs)
        self.fields['song_list'] = forms.ModelChoiceField(queryset=Song.objects.filter(owner=None) | Song.playlist.objects.filter(owner=user), required=False)

Answer 2

OK, my bad. Didn't read enought to see problem lies in the form, But according to this post: https://stackoverflow.com/a/5122029/2695295 you could rewrite your for like this:

class SongInfoForm(forms.Form):
    def __init__(self, user, *args, **kwargs):
        self.user = user
        super(SongInfoForm, self).__init__(*args, **kwargs)

    selected_songs = Song.objects.filter(owner=None) | Song.objects.filter(owner=user.id)
    song_list = ModelChoiceField(queryset=selected_songs, required=False)

and then in view create your form like this:

form = SongInfoForm(request.user, initial={'song_list': song.song_list})

this way form object should have access to user.