从find命令对目标文件执行多个命令

Question

Let's say I have a bunch of *.tar.gz files located in a hierarchy of folders. What would be a good way to find those files, and then execute multiple commands on it.

I know if I just need to execute one command on the target file, I can use something like this:

$ find . -name "*.tar.gz" -exec tar xvzf {} \; 

But what if I need to execute multiple commands on the target file? Must I write a bash script here, or is there any simpler way?

Samples of commands that need to be executed a A.tar.gz file:

$ tar xvzf A.tar.gz   # assume it untars to folder logs
$ mv logs logs_A
$ rm A.tar.gz

Answer 1

Writing a shell script is probably easiest. Take a look at sh for loops . You could use the output of a find command in an array , and then loop over that array to perform a set of commands on each element.

For example,

arr=( $(find . -name "*.tar.gz" -print0) )
for i in "${arr[@]}"; do
    # $i now holds each of the filenames output by find
    tar xvzf $i
    mv $i $i.suffix
    rm $i
    # etc., etc.
done

Answer 2

Here's what works for me (thanks to Etan Reisner suggestions)

    #!/bin/bash    # the target folder (to search for tar.gz files) is parsed from command line
    find $1 -name "*.tar.gz" -print0 | while IFS= read -r -d '' file; do    # this does the magic of getting each tar.gz file and assign to shell variable `file`
        echo $file                        # then we can do everything with the `file` variable
        tar xvzf $file
        # mv untar_folder $file.suffix    # untar_folder is the name of folder after untar
        rm $file
    done

As suggested, the array way is unsafe if file name contained space(s), and also doesn't seem to work properly in this case.