[英]Javascript regex all matches
I'm trying to find a couple things in my source through regex, but I can't get it to returns all the data I need.我试图通过正则表达式在我的源中找到一些东西,但我无法让它返回我需要的所有数据。 The regex I use I've tested it on regex101 and works just fine I think.
我使用的正则表达式我已经在regex101上测试过,我认为它工作得很好。
My source:我的来源:
/**
* @author person1
* @author person2
*/
console.log('a');
What I want is to retrieve person1 and person2.我想要的是检索person1和person2。
My code:我的代码:
fs.readdir('./src', function (err, files) {
for (var i = 0; i < files.length; i++ ) {
var file = files[i];
fs.readFile('./src/' + file, { encoding: 'utf-8' }, function (err, data) {
if (err)
throw err;
var matches = (/@author (.*)$/gm).exec(data);
console.log(matches);
});
}
});
When ran this only returns person1 not person2.运行时只返回 person1 而不是 person2。 Is my regex wrong or what am I missing?
我的正则表达式错了还是我错过了什么?
A RegExp object is stateful, and retains the index of the latest match, to continue from there. RegExp 对象是有状态的,并保留最新匹配项的索引,以从那里继续。 Thus, you may want to run the regex several times in a loop.
因此,您可能希望在循环中多次运行正则表达式。
var match, authors = [];
var r = /@author (.*)$/gm;
while(match = r.exec(data)) {
authors.push(match[1]);
}
You can also use data.match(...)
, but this won't extract the match groups.您也可以使用
data.match(...)
,但这不会提取匹配组。
Now a days you can use String.prototype.matchAll
现在你可以使用
String.prototype.matchAll
const s = ` /** * @author person1 * @author person2 */ console.log('a'); `; const re = /@author\\s+(.*)$/gm; const people = [...s.matchAll(re)].map(m => m[1]); console.log(people);
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