PHP-file_get_contents跟随标题刷新
[英]PHP - file_get_contents follow header refresh
问题描述
I have a script that use the 
我有一个脚本使用
header('Refresh: 5; url=http..');
die();
And i call this script with another php file that use the function "file_get_contents". 我用另一个使用函数“ file_get_contents”的php文件调用此脚本。 Unfortunately it does not work. 不幸的是，它不起作用。 With header location there aren't problems. 头位置不存在问题。
Any suggestions? 有什么建议么？
-- UPDATES -- - 更新 -
I have followed the advice of Oscargeek. 我听了Oscargeek的建议。 I have updated the code with a print of HTML that contains meta-refresh. 我已经用包含元刷新的HTML打印更新了代码。 The script that call this url, is a "system" of cron, and make this call in a foreach. 调用此URL的脚本是cron的“系统”，并在foreach中进行此调用。 So i think it can't work. 所以我认为这行不通。 I have changed this call with a cron and wget, but the result is the same. 我已经使用cron和wget更改了此调用，但是结果是相同的。
Other suggestion ? 还有其他建议吗？
2 个解决方案
解决方案1
1 2015-07-16 08:28:46
When you are doing a file_get_contents, you get the HTML but not the headers of the first page. 在执行file_get_contents时，您将获得HTML而不是首页的标题。
file_get_contents only return a string without headers, header location it's working because are doing the redirection before return this string. file_get_contents仅返回不包含标题的字符串，它起作用的标题位置是因为在返回此字符串之前正在执行重定向。
Try to do the redirect from the HTML, in your first page write this content: 尝试从HTML进行重定向，在您的第一页中编写以下内容：
<html>
<head>
<meta http-equiv="refresh" content="5; url=http://google.com" />
</head>
</html>
In the PHP that you are calling, you should only print this content without other data and the refresh will do. 在要调用的PHP中，只应打印此内容，而不打印其他数据，刷新即可。
解决方案2
0 2015-07-16 08:36:43
Okay, first of all, I'm wondering why you use file_get_contents to include a PHP-File. 好的，首先，我想知道为什么您使用file_get_contents来包含一个PHP文件。 I'd use include or require. 我会使用include或require。
For your problem some additional information: 对于您的问题，一些其他信息：
The problem is: None of those headers ever was running in your other script. 问题是：这些标头中的任何一个都没有在其他脚本中运行。 So this means IF they are send, they got send by the file you were trying to read - but: Since the script didn't got send via HTTP-Protocol, it doesn't send. 因此，这意味着如果它们已发送，它们是通过您尝试读取的文件发送的-但是：由于该脚本未通过HTTP协议发送，因此不会发送。
If you want to use it like this, I'd advice you to use HTML-Refresh like Oscargeek stated, or use Include / Require, if you want to keep PHP-Code. 如果您想像这样使用它，我建议您使用Oscargeek所述的HTML-Refresh，或者如果要保留PHP代码，则使用Include / Require。
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.