[英]How to get a part of a url string with pure javascript
I have this url, for example: 我有这个网址,例如:
https://www.google.com/calendar/render#main_7%7Cmonth
I need to get ONLY calendar
with or witout /
我只需要带或不带
calendar
/
Why in pure JavaScript? 为什么使用纯JavaScript? I want to put it in a bookmark, so i cant use any kind of JS.Framework...
我想把它放在书签中,所以我不能使用任何类型的JS.Framework ...
Some of you could say that post is duplicated. 你们中有些人可能会说帖子重复了。 Thats why you dont use the search-tool nor read the entire question.
这就是为什么您不使用搜索工具也不阅读整个问题的原因。 Thanks for other who really read everything.
感谢其他真正阅读所有内容的人。
PD:Yeah, i've readed this solution.. this does not fit me. PD:是的,我已经阅读了此解决方案..这不适合我。 JavaScript - Get Portion of URL Path
JavaScript-获取部分URL路径
Assuming calendar
is always on the same position you could do 假设
calendar
始终位于您可以执行的位置
var url = 'https://www.google.com/calendar/render#main_7%7Cmonth';
var calendar = url.split('/')[3];
使用split函数将字符串划分为数组:
"https://www.google.com/calendar/render#main_7%7Cmonth".split('/')[3];
(回答这个问题我有点伤心)。
var whatyouwant = url.split('/')[3];
var url = "https://www.google.com/calendar/render#main_7%7Cmonth";
var split_url = url.split('/');
for(var i=0; i < split_url.length; i++)
if(split_url[i] == 'calendar')
alert("It's a calendar");
Search for calendar and extract the remainder of the string - 搜索日历并提取字符串的其余部分-
var s = 'https://www.google.com/calendar/render#main_7%7Cmonth';
var o = s.indexOf('calendar');
if (o !== -1) {
// Found calendar at offset o
console.log(o);
console.log(s.substr(o));
}
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