捕获div另一个页面或jQuery javascript

Question

I want to load in a local page , only the elements LOGIN , PASSWORD , REGISTER , another external page in another domain, without loading the entire layout of it , only these three elements. 我想只在本地页面中加载元素LOGIN，PASSWORD，REGISTER，另一个域中的另一个外部页面，而不加载它的整个布局，仅加载这三个元素。

I've tried that way , seeking to identify the element: 我尝试过这种方法，试图确定元素：

$.ajax({
    url: 'http://www.sptrans.com.br/sac/solicitacoes.aspx',
    type: 'GET',
    success: function(res) {
        var headline = $(res.responseText).find('vUSRLOGA'); 
        $("#conteudo").html(headline);
    }
});

and 和

$.ajax({
            url: 'http://www.sptrans.com.br/sac/solicitacoes.aspx',
            type: 'GET',
            success: function(res) {
                var headline = $(res.responseText).text();
                $("#conteudo").html(headline);
            }
        })

I want the elements normally be presented in order to give login or register . 我希望通常显示这些元素以便进行登录或注册。

the current way , behind only the text of the page and not the functional elements 当前方式，仅在页面文本后面，而不在功能元素后面

Full Code: 完整代码：

<!DOCTYPE HTML>
<html lang="pt-br">

<head>
<!-- Scripts Javascript -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script type="text/javascript" src="http://projetos.lucaspeperaio.com.br/ajax-cross-domain/jquery.xdomainajax.js"></script>

<script type="text/javascript">
/*$.ajax({
            url: 'http://www.sptrans.com.br/sac/solicitacoes.aspx',
            type: 'GET',
            success: function(res) {
                var headline = $(res.responseText).text();
                $("#conteudo").html(headline);
            }
        });*/

        $.ajax({
    url: 'http://www.sptrans.com.br/sac/solicitacoes.aspx',
    type: 'GET',
    success: function(res) {
        var headline = $(res.responseText).find('vUSRLOGA'); 
        $("#conteudo").html(headline);
    }
}); 

</script>


<title>Teste</title>
<body>




    <div id="conteudo" style="background:#EEF0A6"></div>


</body>
</html>

I want to show ONLY the part that is inside the red square: 我只想显示红色方块内的部分：

Answer 1

As I understood, you have a website that wants access another website. 据我了解，您有一个网站想要访问另一个网站。 It can't be done in javascript because of cross-domain policy. 由于跨网域政策，因此无法在JavaScript中完成。

Find element attributes on different domain using Javascript 使用JavaScript在其他域上查找元素属性

捕获div另一个页面或jQuery javascript

问题描述

1 个解决方案

解决方案1
1 已采纳 2015-07-16 17:27:56

捕获div另一个页面或jQuery javascript

问题描述

1 个解决方案

解决方案1 1 已采纳 2015-07-16 17:27:56

解决方案1
1 已采纳 2015-07-16 17:27:56