通过shell变量将配置选项传递给git clone

Question

I'm trying to pass dynamically created configuration options to git clone via an environment variable on bash.

Passing them directly works, but it does not work via the env variable:

$ git clone -c 'url.foo.insteadof=bar' git://git.cweiske.de/psist.git
... all fine

$ export PARAMS="-c 'url.foo.insteadof=bar'"; git clone $PARAMS git://git.cweiske.de/psist.git
error: invalid key: 'url.foo.insteadof

What can I do to make git recognize the options?

Answer 1

That's because in the first example the quotes are syntactic:

$ (set -o xtrace; git clone -c 'url.foo.insteadof=bar' git://invalid) 2>&1 | grep 'git clone'
+ git clone -c url.foo.insteadof=bar git://invalid

while in the second they are literal:

$ (set -o xtrace; export PARAMS="-c 'url.foo.insteadof=bar'" && git clone $PARAMS git://invalid) 2>&1 | grep 'git clone'
+ git clone -c ''\''url.foo.insteadof=bar'\''' git://invalid

You can use arrays to reliably pass arguments using variables :

$ (set -o xtrace; export PARAMS=('-c' 'url.foo.insteadof=bar') && git clone "${PARAMS[@]}" git://invalid) 2>&1 | grep 'git clone'
+ git clone -c url.foo.insteadof=bar git://invalid

Answer 2

You could use eval to get the parameters passed correctly.

export PARAMS="-c 'url.foo.insteadof=bar'"; 
eval git clone $PARAMS git://git.cweiske.de/psist.git