[英]Regex Match In Multiple Of n
I want to match a string that starts with at least 4 spaces and in multiples of 4. So 4, 8, 12. 我想匹配一个以至少4个空格和4的倍数开头的字符串。所以4、8、12。
What i've got so far only matches at least 4 spaces.So it accepts 4, 5, 6... 到目前为止,我只匹配至少4个空格。所以它接受4,5,6 ...
/^[\s]{4,}\+/
Put the pattern which matches exactly four spaces inside a group and then make that group to repeat one or more times. 将与四个空格完全匹配的模式放在一个组中,然后使该组重复一次或多次。 And also you need to add a negative lookahead at the end, so that it won't match the string which has four spaces at the start followed by another space.
另外,您还需要在末尾添加负前行,以使其与开头有四个空格后跟另一个空格的字符串不匹配。
/^(?:\s{4})+(?! )/
var s = " I have four spaces" var s1 = " I have five spaces" alert(/^(?:\\s{4})+(?! )/.test(s)) alert(/^(?:\\s{4})+(?! )/.test(s1))
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