遍历表达式树并提取参数

Question

I'm writing a kind of a mapping tool. I have a method that looks like this (simplified):

   public void RegisterMapping<TTarget, TSource>(string propertyName, 
                                                 Expression<Func<TSource, object>> memberMap)

The memberMap is an expression defining how to transform a property from TSource to TTarget . For the business logic, I need to extract all references to properties of TSource from it. For example, from

x => x.Customers.Where(c => c.Orders.Any())

I would like to get Customers , and from

x => x.FirstName + " " + x.LastName

FirstName and LastName (could be as string[], PropertyInfo is trivial to convert to).

How would I do this? My first approach was to traverse the tree manually, checking the node type and inspecting different properties depending on the node type (eg Operand for unary expressions, Arguments for a function call) to determine of any of these are a property of TSource . Then I discovered the expression kind list and I gave up -- even if I support only the most common kinds, it's still lots of work. Then I found the ExpressionVisitor . It looks better, but it's still a lot of work to override the visitor methods and I'd like to know if there's an other option, using perhaps a more specialised framework, before I devote my time to this.

Answer 1

I think as you've said that using ExpressionVisitor works out to be a good approach. You don't need to implement all the Visit... methods as they already have a default implementation. From what I understood what you want is to find all property accesses of a certain type inside a lambda function

public class MemberAccessVisitor : ExpressionVisitor
{
    private readonly Type declaringType;
    private IList<string> propertyNames = new List<string>();

    public MemberAccessVisitor(Type declaringType)
    {
        this.declaringType = declaringType;
    }

    public IEnumerable<string> PropertyNames { get { return propertyNames; } }

    public override Expression Visit(Expression expr)
    {
        if (expr != null && expr.NodeType == ExpressionType.MemberAccess)
        {
            var memberExpr = (MemberExpression)expr;
            if (memberExpr.Member.DeclaringType == declaringType)
            {
                propertyNames.Add(memberExpr.Member.Name);
            }
        }

        return base.Visit(expr);
    }
}

This could be further improved to what you want by checking the member is a property and also to get PropertyInfo rather than strings

It could be used as follows:

var visitor = new MemberAccessVisitor(typeof(TSource));

visitor.Visit(memberMap);

var propertyNames = visitor.PropertyNames;