如何通过大量查询数据加快PHP到MySQL查询的速度

Question

Before code : for loop should run at least 143,792,640,000 times and create the table at least produce 563,760 rows without duplicated I want to know how to speed up or something parallel computing like Hadoop that could accelerate between php and MySQL.

Code below:

MySQL connection

$link=mysql_connect($servername,$username,$password);
mysql_select_db($dbname);
$sql= "INSERT INTO EM (source,target) VALUES ";

for loop read data into MySQL check function if duplicate not insert and update count=count+1

for($i=0;$i<$combine_arr_size;$i++){
    for($j=0;$j<$combine_arr_size;$j++){  

//below check if find the duplicated like a,b we recognize b,a is same thing

if(check($combine_words_array[$i],$combine_words_array[$j])) {
                $update_query="UPDATE EM SET count = count+1 where (source='$combine_words_array[$i]' AND target='$combine_words_array[$j]') OR (source='$combine_words_array[$j]' AND target='$combine_words_array[$i]');";
                mysql_query($update_query);
            } else {
                if (!$link) {
                    die("Connection failed: " . mysql_error());
                }

//else using insert into table () value to concatenate the string

    $sql.="('$combine_words_array[$i]','$combine_words_array[$j]'),";     
            mysql_query(substr($sql,0,-1));
            $sql= "INSERT INTO EM (source,target) VALUES ";        
        }
    }
} 

read the all vector align from comebine_word_array[] to combine_word_array[]

below is check function , check if find the pair return value

function check($src, $trg) {
    $query = mysql_query("SELECT * FROM EM WHERE (source='$src' AND target='$trg') OR (source='$trg' AND target='$src');");
    if (mysql_num_rows($query) > 0) {
        return 1;
    } else {
        return 0;
    }
}

table

+--------+--------------+------+-----+---------+-------+
| Field  | Type         | Null | Key | Default | Extra |
+--------+--------------+------+-----+---------+-------+
| source | varchar(255) | YES  |     | NULL    |       |
| target | varchar(255) | YES  |     | NULL    |       |
| count  | int(11)      | NO   |     | 0       |       |
| prob   | double       | NO   |     | 0       |       |
+--------+--------------+------+-----+---------+-------+

now the php code just influence the source ,target and count

Answer 1

Put a better processor on your server and increase the RAM, then go to your php.ini settings and raise the maximum allocated memory for all the various memory/processor relative configurations.

This will empower the server further and improve the running efficiency.

If you cannot find your php.ini file. Create a new php file with the following contents and open it in the browser:

<?php phpinfo(); ?>

Make sure you delete this file after finding out where php.ini is... as an unwanted user (hacker) could find this file and it would give them detailed information leading to vulnerabilities in your server configuration.

Once you've found php.ini, do some looks online to determine settings that are not obvious and increase the memory allocations in various areas.

Answer 2

It is difficult to know exactly what you want to do with duplicate combinations. For example you are getting every combination of the array, which is going to get lots of duplicates which you will then count twice.

However I would be tempted to load the words into an table (possibly a temp table) and then do a cross join of the table against itself to get every combination, and use this to do an INSERT with an on duplicate key clause.

Very crudely, something like this:-

<?php

$sql = "CREATE TEMPORARY TABLE words
        (
            word varchar(255),
            PRIMARY KEY (`word`),
        )";

$link = mysql_connect($servername,$username,$password);
mysql_select_db($dbname);
$sql = "INSERT INTO words (word) VALUES ";
$sql_parm = array();

foreach($combine_words_array AS $combine_word)
{
    $sql_parm[] = "('".mysql_real_escape_string($combine_word)."')";
    if (count($sql_parm) > 500)
    {
        mysql_query($sql.implode(',', $sql_parm));
        $sql_parm = array();
    }
}

if (count($sql_parm) > 0)
{
    mysql_query($sql.implode(',', $sql_parm));
    $sql_parm = array();
}

$sql = "INSERT INTO EM(source, target)
        SELECT w1.word, w2.word
        FROM words w1
        CROSS JOIN words w2
        ON DUPLICATE KEY UPDATE `count` = `count` + 1
        ";

mysql_query($sql);

This does rely on having a unique key covering both the source and target columns.

But whether this is an option depends on the details of the records. For example with your current code if there were 2 words (say A and B) you would find the combination A / B and the combination B / A. But both combinations would update the same records