php while循环附加条件不符合预期

Question

I have this piece of code:

        $i=0;
        while ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)){
*(line 133)*    if (array_search("SUCCESS", $row) != false) {
                echo "<tr class='success'>";
            }
            elseif (array_search("ERROR", $row) != false) {
                echo "<tr class='danger'>";
            }
            else {
                echo "<tr>";
            }
                foreach ($row as $rowData) {
                    if ($rowData == "SUCCESS") {
                        echo "<td><span class='mdi-navigation-check'></span></td>";
                    }
                    elseif ($rowData == "ERROR") {
                        echo "<td><span class='mdi-navigation-close'></span></td>";
                    }
                    else {
                        if (gettype($rowData) == "object") {
                            echo "<td>" . $rowData->format('Y-m-d H:i:s') . "</td>";
                        } else {
                            echo "<td>" . $rowData . "</td>";
                        }
                    }
                }
                if (isset($row["cMsgID"])) {
                    echo "<td><a href='#' onclick='window.open(\"/monitor/templates/history.php?cMsgID=" . $row["cMsgID"] . "\", \"history\", \"status=1, toolbar=1 width=800px, height=400px\")'>History</a></td>";
                }
            echo "</tr>";
            $i++;
        }

But when I add a second condition to the while loop the $row variable becomes a boolean true :

$i
while ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC) && $i < 10){
*same code as above*}

First php error message: Warning: array_search() expects parameter 2 to be array, boolean given in C:\\wamp32bit\\www\\monitor\\templates\\mainContent.php on line 133

I have searched for this problem but all of them were related to wrong syntax or the conditions excluding each other.

Why does this happen?

Answer 1

Your problem here is just syntax, that way you are assigning always a boolean value to the $row.

$row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC) && $i < 10

The right way to do this is

($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)) && $i < 10

In the last case you can put an if statment inside the loop, like this:

$i=0 while ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)){ if ($i < 10) { *do something* } else { break; } }

Answer 2

你为什么不试试这个？

while($i < 10){ while($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)){ your code here; } }

Answer 3

Another way you could do it would be :

$i=0;    
while (true == ($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)) && $i < 10) {
    *code*
    $i++;
}