正则表达式-忽略Word + HTML内部

Question

trying to select the word "content" (using javascript) with my limited regex knowledge from the below:

 Here is content <p>content</p> content. Content contentpeople peoplecontent peoplecontentpeople 

With the regex:

 ([\\S]*)content([\\S]*) 

This gets me "content" without the spaces but is also bringing back the P tag and "peoplecontent" - I only want if its not part of another word. I need to chain some NOTs together right?

Answer 1

使用\\b ，即单词边界元字符，即

/\bcontent\b/g