每个人有两个ID的总行数

Question

I have two tables, one with people and one with values. Each person can have two IDs and I need the values assigned to their IDs in the second table to sum with each other (so all of ID1's values would be a single value that is also combined with ID2's values).

Table a
ID  ID2 FName
1   4   Jacob
56  13  John

Table b
ID  AID V1  V2
1   4   50  25
2   13  30  0
3   1   10  15
4   4   0   5

Goal output
SUM(V1,V2)  a.ID    a.ID2   FName
105         1       4       Jacob
30          56      13      John

I was able to get the value from one ID with

SELECT SUM(V1,V2) AS Total, AID, FName
FROM a,b
WHERE b.AID=a.ID
GROUP BY AID
ORDER BY Total DESC

I'm guessing I need a subquery to do both at once, but I wasn't sure how to work it in.

Answer 1

select
    sum(b.V1 + b.V2) as Total,
    a.ID,
    a.ID2,
    a.FName
from
    a
    inner join b on
        a.ID = b.AID
        or a.ID2 = b.AID
group by
    a.ID,
    a.ID2,
    a.FName;

Does this work? I don't have a way to test it right now.