使用grep regex从arp表中提取MAC地址

Question

I am trying to extract MAC address from arp table without but it is returning a empty line.

I tried to use the command:

arp -a | grep eth1 | grep '^\A(([0-9a-fA-F]{2}):){5}([0-9a-fA-F]{2})$\z'

The 'arp -a' command return:

? (192.168.36.20) at 80:e0:1d:43:b0:60 [ether] on eth1
? (192.168.0.1) at 34:4b:50:b7:ef:08 [ether] on usb0
? (172.17.140.200) at 10:c3:7b:c4:82:04 [ether] on eth0

Thanks

Answer 1

解决了使用：

arp -a | grep eth1 | grep -o -E '([[:xdigit:]]{1,2}:){5}[[:xdigit:]]{1,2}'

Answer 2

A much simpler way using awk :

$ arp | grep eth1 | awk '{print $3}'

See GNU Awk manual for more.