[英]Shell scripting-subdirectories calculation
Write a shell script takes the name a path (eg: /afs/andrew/course/15/123/handin), and counts all the sub directories (recursively). 编写一个shell脚本时,将名称命名为路径(例如:/ afs / andrew / course / 15/123 / handin),并计算所有子目录(递归)。
Ex. 例如 /afs/andrew/course/15/123/handin should give me 6. I tried with the Find command,but the path which i am giving is being accepted.
/ afs / andrew / course / 15/123 / handin应该给我6.我尝试了Find命令,但是我给的路径被接受了。
simple AWK can do that 简单的AWK可以做到
root@freebsd:~ # echo /afs/andrew/course/15/123/handin | awk -F / '{ print NF-1}'
6
root@freebsd:~ #
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