从包含内容的字符串中删除 HTML 标签

Question

I have a string = "195121<span class="up">+432</span>" . I need regEx to remove tags with its content (result string = "195121" )

Answer 1

您可以尝试以下基于捕获组的正则表达式。

string.replaceAll("(?s)<(\\w+)\\b[^<>]*>.*?</\\1>", "");

Answer 2

The main regex works for me are below; It removes all content with a given tag name.

"(?is)<your_tag_name[^>]+>.*?<\\/your_tag_name>"

I manage it this way. Hope it helps others.

var data = "<p>Dhaka is the capital city of Bangladesh " +
    "and many palaces and mosques remain. This is" +
    " fast-growing modern metropolis.</p>\\r\\n<p>&lt;flightnode to=\"CXB\"&gt;&lt;/flightnode&gt;</p>"

First replace &lt; and &gt; to < and >

// This replacement not needed if it's already been there
data = data.replace("&lt;", "<").replace("&gt;", ">")

Then print & check it.

println("\n\n $data")

> //output //-> <p>Dhaka is the capital city of Bangladesh and many
> palaces and mosques remain. This is fast-growing modern
> metropolis.</p><p><flightnode to="CXB"></flightnode></p>

Set tags array you want to remove with its elements ;

val tag = arrayOf("flightnode", "hotelnode ", "packagenode")

Then loop throught your string

for (value in tag) {
    val patternString = "(?is)<$value[^>]+>.*?<\\/$value>"
    val pattern = compile(patternString)
    val matcher = pattern.matcher(data)
    println("\n\n" + matcher.find())
    data = matcher.replaceAll("")
}

Print to check it.

println("\n\n" + data)

> // output // -> <p>Dhaka is the capital city of Bangladesh and many
> palaces and mosques remain. This is fast-growing modern
> metropolis.</p>\r\n<p></p>

Thanks my ex-colleague @masud-bappy for creating regex.