Python-从main（）中的另一个python文件调用2个函数

Question

I created 2 different python files. The first file named "game.py" has the code:

h = int(input("Pick number 1 or 2: "))

def game():

    if h == 1:
        print ("You lose!")
    if h == 2:
        print ("You win!")

def play_again():

    rounds = input("Play again? (Y/N): ")
    if rounds == "Y":
        game()
    if rounds == "NO":
        print ("Game Over")

As shown, I have 2 functions in this file.

Then I created another file with my main function that calls these 2 functions. The following is the code inside it:

import game

def main():

    game.game()

    game.play_again()

main()

When I run this on the console, it prints "Pick number 1 or 2: ". But if I run it again, it prints "Play again? (Y/N): ".

How do I fix this so that it only prints "Pick number 1 or 2 : " whenever I run the code?

Answer 1

maingame.py:

import game

game.game()

if __name__ == "__main__":
    print("maingame.py is being run directly")
else:
    print("maingame.py is being imported into another module")

game.py:

def game():
    h = input("Pick number 1 or 2:\n")
    if h == 1:
        print("You lose!")
    if h == 2:
        print("You win!")
    play_again()

def play_again():
    rounds = raw_input("Play again? (Y/N): ") # just use input() for python3
    if rounds == 'Y':
        game()
    if rounds == 'N':
        print("Game Over")

See also: What does if __name__ == "__main__": do?

and: Python 2.7 getting user input and manipulating as string without quotations

You can delete the three bottom lines from maingame.py but you should read the associated link to understand what if __name__ == "__main__": does and why. Normally you would just write:

if __name__ == "__main__":
    main()

And this will ensure that your file will run, beginning with main(), when called from the command line.