如何使用php从mysql导出数据

Question

I wanted to fetch some data from database and those data will be downloadable in text format.

For that I am using

<?php
$filename="abc.txt";
header("Content-Disposition: attachment; filename=\"$filename\"");
header("Content-Type: text/csv");
echo "PHP is awesome";
?>

The above code is providing the option to download a file.

But when I am trying to add database connection in code that time I am not getting the download option. So I need help to solve the above problem.

My error Code:

<?php
$filename="abc.txt";
header("Content-Disposition: attachment; filename=\"$filename\"");
header("Content-Type: text/csv");
$name="JONE":
$db_host =hostname;
$db_user =username;
$db_pass =password;
echo "$name";
mysql_connect( $db_host, $db_user, $db_pass );
$sql_query="select * from order";
echo "$sql_query";
$result = mysql_query($sql_query) or die('MySql Error' . mysql_error());
while ( $array = mysql_fetch_array($result) )
{
   echo "$array[0]\n";
}
?>

Answer 1

which PHP version used?

The mysql extension is deprecated in php 5 later

PHP 5 and later can work with a MySQL database using:

MySQLi extension (the "i" stands for improved)

PDO (PHP Data Objects)

Earlier versions of PHP used the MySQL extension. However, this extension was deprecated in 2012.

if you used php new version and mysql

you can try for your code

<?php
$filename="abc.txt";
header("Content-Disposition: attachment; filename=\"$filename\"");
header("Content-Type: text/csv");
$name="JONE";
$DBServer = 'localhost'; // e.g 'localhost' or '192.168.1.100'
$DBUser   = 'root';
$DBPass   = 'root';
$DBName   = 'sms';
echo "$name";
$conn = new mysqli($DBServer, $DBUser, $DBPass, $DBName);

// check connection
if ($conn->connect_error) {
  trigger_error('Database connection failed: '  . $conn->connect_error,
  E_USER_ERROR);
} 

$sql_query="select * from tmd_news";
$rs=$conn->query($sql_query);

if($rs === false) {
trigger_error('Wrong SQL: ' . $sql_query . ' Error: ' . $conn->error, 
E_USER_ERROR);
} else {
 $arr = $rs->fetch_all(MYSQLI_ASSOC);
}
foreach($arr as $row) {
echo $row['news_id'];
}
?>