[英]sympy: how to sympify logical “NOT”
The following code would work to sympify logical expressions: 以下代码可用于表达逻辑表达式:
sympify('a&b') # And(a, b)
sympify('a|b') # Or(a, b)
But how do I get a result of Not(a)
? 但是如何得到
Not(a)
的结果呢?
It turns out the symbol you are looking for is ~
. 事实证明你要找的符号是
~
。 See the following: 请参阅以下内容:
>>> from sympy import sympify
>>> sympify('a&b')
And(a, b)
>>> sympify('a|b')
Or(a, b)
>>> sympify('~a')
Not(a)
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