[英]Convert network request from synchronous to asynchronous (PHP/Javascript)
I actually use a php script for an advertising network, but the code that publisher will use is synchronous. 我实际上在广告网络中使用了php脚本,但是发布者将使用的代码是同步的。 Now, I want that the script will load asynchronous.
现在,我希望脚本将异步加载。
Do I need to change all the PHP/Javascript code ? 我是否需要更改所有PHP / Javascript代码? OR there is a trick to use (javascript library...)
或者有一个使用技巧(javascript库...)
Thank you for your help ! 谢谢您的帮助 !
Synchronous/Asynchronous depends on the client side. 同步/异步取决于客户端。 Unless very particular exceptions.
除非非常特殊的例外。
So focus on Javascript code .: https://developer.mozilla.org/en-US/docs/Web/API/XMLHttpRequest/Synchronous_and_Asynchronous_Requests 因此,请专注于Javascript代码 。: https : //developer.mozilla.org/zh-CN/docs/Web/API/XMLHttpRequest/Synchronous_and_Asynchronous_Requests
EDIT Example: send a file to the console log 编辑示例:将文件发送到控制台日志
This is the simplest usage of asynchronous XMLHttpRequest. 这是异步XMLHttpRequest的最简单用法。
var xhr = new XMLHttpRequest();
xhr.open("GET", "http://bar/foo.txt", true/*ASYNCHRONOUS*/);
/* here is registered what-to-do once xhr is 'done':
it can happens anywhen, it is Asynchronous: */
xhr.onload = function (e) {
if (xhr.readyState === 4) {
if (xhr.status === 200) {
console.log(xhr.responseText);
} else {
console.error(xhr.statusText);
}
}
};
xhr.onerror = function (e) {
console.error(xhr.statusText);
};
xhr.send(null);
A contrario , this is synchronous : 相反 ,这是同步的 :
var request = new XMLHttpRequest();
request.open('GET', 'http://...', false/*ASYNCHRONOUS=false, it is SYNCHRONOUS)*/
request.send(null);
/*anything else is stopped around, one thread working only:request*/
/*once it is done, the next line is executed. This is:*/
if (request.status === 200) {
console.log(request.responseText);
}
So get where JS Sync method is done in your JS code and change one for the other. 因此,请在您的JS代码中获取完成JS Sync方法的位置,然后将其中一个更改为另一个。
I'm not completely sure, but i think jQuery Ajax call is what yo want. 我不确定,但我认为jQuery Ajax调用是您想要的。 http://api.jquery.com/jquery.ajax/
http://api.jquery.com/jquery.ajax/
Here is sample ajax call: 这里是示例ajax调用:
$.ajax({
url: formURL,
type: "POST",
data: postData,
beforeSend: function() {
//this code always run Ususaly UI changes
},
success: function(data, textStatus, jqXHR) {
//var result = JSON.parse(data);
},
error: function(jqXHR, textStatus, errorThrown) {
//if ajax fails
},
complete: function(response) {
// this code always run Ususaly UI changes
}
});
Also since PHP always returns string, for success you can simply use: 同样,由于PHP总是返回字符串,因此,您可以简单地使用以下命令来获得成功:
"echo $string;"
If you want to return an array you should: 如果要返回数组,则应该:
"echo json_encode($array);"
For the error part it is better to force PHP to return error somethng like: 对于错误部分,最好强制PHP返回错误,例如:
header('HTTP/1.1 422 Unprocessable Entity');
header('Content-Type: application/json; charset=UTF-8');
die(json_encode($errors));
exit;
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