将相同的事件处理代码附加到jquery中的多个事件

Question

i have an input element, and i want bind both change and keypress event with the input, but event handling code is same for both the events. is there any short way of doing this instead of writing the same code twice. well, i could write a method, but wanted to see if there is any easier way of doing this

$("#inpt").change(function(){
   some code
});

$("#inpt").keypress(function(){
   same code
});

is there any way i can bind both events?

Answer 1

You can use the jQuery on method.

$("#inpt").on( "change keypress", function () {
     code
});

Answer 2

You can save the function and bind it to both:

var fn = function(){ /*some code*/ };
$("#inpt").change(fn).keypress(fn);

Answer 3

You can also use the 'live' event instead of the 'bind' one sugested. The 'live' event will cover even dynamic created elements. (Deprecated on 1.7)

Kaless1n and Matthew, to bind to multiple elements use the "Attribute Starts With Selector":

var fn = function() { /*some code*/ };

$('input[id^="foo_"]').click(fn).keyup(fn).keydown(fn);

That will bind to all 'input' elements where the 'id' starts with 'foo_'. You can change 'input' to any onther element and/or the 'id' with the 'name' attribute for example.