简体   繁体   English

比较DB2中的两列

[英]Compare two columns in DB2

I need help with a query DB2. 我需要有关查询DB2的帮助。

My table looks like this: 我的桌子看起来像这样:

IP_ID         IP_TYPE_CDE UPDT_DT_TM                
------------- ----------- --------------------------
47560147.          39 2012-11-06-04.16.21.000000
47560147.         319 2013-06-12-16.54.09.000000
47560002.          39 2012-11-06-04.16.21.000000
47560002.         319 2013-06-12-16.54.09.000000
47560003.          39 2012-11-06-04.16.21.000000
47560003.          39 2013-06-12-16.54.09.000000

I need to scan the database, catch all the IP_ID and compare it to that IP_ID had change in IP_TYPE_CDE. 我需要扫描数据库,捕获所有IP_ID并将其与IP_TYPE_CDE中已更改的IP_ID进行比较。

Ie, in this case it should return only IP_ID 47560147 and 47560002. 即,在这种情况下,它应该仅返回IP_ID 47560147和47560002。

You could group by ip_id and filter by a having clause that counts the distinct number of ip_type_cde s: 您可以按ip_id分组, ip_id having计数ip_type_cde的不同数量的ip_type_cde子句进行过滤:

SELECT   ip_id
FROM     mytable
GROUP BY ip_id
HAVING   COUNT (DISTINCT ip_type_cde) > 1

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM