[英]SQL subsets query
I am having trouble creating a query for an SQL table. 我在为SQL表创建查询时遇到问题。 The query I am trying to create shows the number of products within the category of "clothes" and does not show accessories for example a list of products that are entered as T-shirts or sweatshirts.
我尝试创建的查询显示“衣服”类别中的产品数量,而不显示配件,例如输入为T恤或运动衫的产品列表。
Here is the tables that have been created: 这是已创建的表:
CREATE DATABASE IF NOT EXISTS product_list;
DROP TABLE IF EXISTS products;
DROP TABLE IF EXISTS product_categories;
DROP TABLE IF EXISTS categories;
CREATE TABLE products (
product_id INT AUTO_INCREMENT PRIMARY KEY,
title VARCHAR(50) DEFAULT NULL,
active BOOL DEFAULT NULL
);
CREATE TABLE categories (
category_id INT AUTO_INCREMENT PRIMARY KEY,
name VARCHAR(50),
structure VARCHAR(50)
);
CREATE TABLE product_categories (
product_id INT,
category_id INT,
PRIMARY KEY(product_id, category_id)
);
INSERT INTO products VALUES
(NULL, "Blue Sweatshirt", false),
(NULL, "Short Sleeve T-Shirt", true),
(NULL, "White Vest", true),
(NULL, "Black Hairclip", true),
(NULL, "Knitted Hat", false),
(NULL, "Grey Sweatshirt", true),
(NULL, "Tartan Scarf", true);
INSERT INTO categories VALUES
(NULL, "Sweatshirts", "Clothes>Sweatshirts"),
(NULL, "T-Shirts", "Clothes>T-Shirts"),
(NULL, "Accessories", "Accessories"),
(NULL, "Winter", "Clothes>Winter"),
(NULL, "Vests", "Clothes>Vests");
INSERT INTO product_categories VALUES
(1, 1), (2, 2), (3, 5), (3, 4), (4, 3), (5, 3), (5, 4), (6, 1), (7, 3), (7, 4);
If I understand correctly, this is a set-within-sets query. 如果我理解正确的话,这是组内查询。 You are looking for products that have at least one "clothes" category, and none of the categories are not clothes.
您正在寻找的商品至少具有一个“衣服”类别,并且所有类别都不是衣服。 I approach this using
group by
and having
because it is quite flexible: 我使用
group by
进行处理having
因为它非常灵活:
select pc.product_id
from Product_categories pc join
categories c
on pc.category_id = c.category_id
group by pc.product_id
having sum(case when c.structure like 'Clothes%' then 1 else 0 end) > 0 and
sum(case when c.structure not like 'Clothes%' then 1 else 0 end) = 0;
If you just want the count, then you can use this as a subquery and use count(*)
. 如果只需要计数,则可以将其用作子查询并使用
count(*)
。
EDIT: 编辑:
A small note. 一个小笔记。 The question is now tagged with MySQL, which has convenient short-hand for the
having
clause: 现在,该问题已使用MySQL进行了标记,它
having
Have子句的便捷缩写:
having sum(c.structure like 'Clothes%') > 0 and
sum(c.structure not like 'Clothes%') = 0;
Try this query 试试这个查询
select * from products a
join Product_categories b on a.product_id=b.product_id
join categories c on b.category_id=b.category_id
where c.name like '%Clothes%'
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