单击按钮后如何将一个图像更改为另一个图像

Question

I have 2 images, using the else-if method, how do I make it so that when I click on image A, it turns to image B and if its image B, turn back to image A? Here is my codes:

private void Smalltubbutton1_Click(object sender, EventArgs e)
{
   if(System.Drawing.Bitmap bitmap1 =
      WindowsFormsApplication21.Properties.Resources.smalltub)
   {
         System.Drawing.Bitmap bitmap1 = 
                        WindowsFormsApplication21.Properties.Resources.GRAYSCALEsmalltub;
   }
   else
   {
     System.Drawing.Bitmap bitmap1 = 
                    WindowsFormsApplication21.Properties.Resources.smalltub      
   }
}

Answer 1

You could do that someway like this:

private bool flag;
private void Smalltubbutton1_Click(object sender, EventArgs e)
{
    System.Drawing.Bitmap bitmap1;

    if (flag)
    {
        bitmap1 = WindowsFormsApplication21.Properties.Resources.GRAYSCALEsmalltub;
    }
    else
    {
        bitmap1 = WindowsFormsApplication21.Properties.Resources.smalltub      
    }

    flag = !flag;
}

Answer 2

You can use a PictureBox and change the image property with your proper image and change a boolean property or variable each time you click on that.

private void pictureBox1_Click(object sender, EventArgs e)
{
      if (flag)
           pictureBox1.Image = WindowsFormsApplication21.Properties.Resources.GRAYSCALEsmalltub;
      else
           pictureBox1.Image = WindowsFormsApplication21.Properties.Resources.smalltub;
      flag=!flag;
}

I hope this would solve your problem. Good Luck.