[英]ZMQ message_t.data() clear data
In reference to this question: Zeromq: How to access tcp message in c++参考这个问题: Zeromq: How to access tcp message in c++
I managed to create a helloworld server that can print the contents of the sent messages pretty easily, however my issue is that I can't figure out a way to clear the buffer in the request variable.我设法创建了一个 helloworld 服务器,它可以很容易地打印发送消息的内容,但是我的问题是我无法找到清除请求变量中缓冲区的方法。
Here's what I mean:这就是我的意思:
When I try and send a request such as:当我尝试发送请求时,例如:
tuna
For some reason the pointer returned by request.data()
is initialised with 6 hexadecimal characters for some reason, and the message sent, after a memcpy
ends up being:出于某种原因,
request.data()
返回的指针出于某种原因用 6 个十六进制字符初始化,并且在memcpy
结束后发送的消息是:
tuna�
If I enter nothing as the message, the message becomes:如果我没有输入任何消息作为消息,消息将变为:
�q���
If I enter enough characters, the characters can overwrite it.如果我输入足够的字符,字符可以覆盖它。 Additionally this data is kept in the variable, even if I re-initialise the
message_t
variable at the start of the loop.此外,这些数据保存在变量中,即使我在循环开始时重新初始化
message_t
变量。 This means that if I send a message of Disestablishmentarianism
, and subsequently send another message of Pro
, the resultant message is proestablishmentarianism
.这意味着,如果我发送了一条
Disestablishmentarianism
的消息,然后又发送了一条Pro
的消息,那么得到的消息就是proestablishmentarianism
。
Here's my code for reference:这是我的代码供参考:
//sender loop
using namespace std;
zmq::context_t context(1);
zmq::socket_t socket(context, ZMQ_REQ);
int main(){
socket.connect("tcp://localhost:28641"); //28641 is the set to be standardised for this kind of communication
string input = "";
cout << "this is the client for communicating with Thalamus.\nTo start, input the name of the module to be used:";
while(true){
std::cout << "Type a config command:" << std::endl;
getline(cin, input);
zmq::message_t request(input.size()+1);
//(char *)request.data() = ' ';
std::string req = std::string(static_cast<char*>(request.data()), request.size());
std::cout << req << std::endl;
//std::cout << input;
memcpy ((void *) request.data (), input.c_str(), input.size());
socket.send (request);
printf("%s\n",(char*)request.data());
// Get the reply.
zmq::message_t reply;
socket.recv (&reply);
std::cout << "response:" << std::endl;
printf("%s\n",(char *)reply.data());
//printf("%s", "moo");
}
return 0;
}
//receiver loop
void Config_Interface(){
//Config_Interaction uses ipc protocols as an interface to controlling and configuring the execution of the program.
/*
requirements:
start stream
stop stream
pause/resume
*/
zmq::context_t config_context(1);
zmq::socket_t config_socket(config_context, ZMQ_REP);
config_socket.bind ("tcp://*:28641");
while(true){
zmq::message_t request;
config_socket.recv(&request);
std::cout << "config update msg received:" << std::endl;
std::string req = std::string(static_cast<char*>(request.data()), request.size());
std::cout << req << std::endl;
//Config_Parse(request.data()); //Function that will parse the command and update the config variables.
std::cout << "--updated config--";
zmq::message_t reply(7);
memcpy ((void *) reply.data (), "got it", 6);
config_socket.send (reply);
}
}
Edit: I've managed to find a work around by using: snprintf ((char *) request.data (),input.size()+1,"%s", input.c_str() );
编辑:我设法使用以下方法找到了解决方法:
snprintf ((char *) request.data (),input.size()+1,"%s", input.c_str() );
instead of memcpy
but I feel as though it still doesn't quite answer the question of why the memory isn't cleared.而不是
memcpy
但我觉得它仍然不能完全回答为什么内存没有被清除的问题。 Maybe I'm missing something fundamental to C++, but even after a ton of searching I still can't find it.也许我遗漏了 C++ 的一些基本知识,但即使经过大量搜索,我仍然找不到它。 :(
:(
you should use你应该使用
message_t(void* data, size_t len) //std::string tmp = "example"; //message_t(tmp.c_str(), tmp.size());
to init初始化
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