使用sed有条件删除xml文件中的行

Question

This question may not have a straight forward answer... if so, not to worry. I have an XML file that looks something like

<a>0.00</a>
<b>0.00</b>
<c>0.00</c>
<d>0.00</d>

This is a dumbed down version of what i'm working with. My goal is to delete any line with a data point of zero, if and only if all data points are zero (as the example i've given above). Even if one of the lines in the file contains a non zero entry, i can't delete any of them. For example if the above was

<a>0.00</a>
<b>0.00</b>
<c>1.00</c>
<d>0.00</d>

then the file should remain untouched. Ultimately, I only want to delete all lines if they all have zero in each and every tag, and leave the file as is otherwise. I know the following will work if all lines have a zero data entry.

sed --in-place '\|>0.00</|d' $FILENAME 

However, if I have the second example below, this will leave me with

<c>1.00</c>

which isn't what I'm looking for. I know I probably need an if statement, something like

if (all lines contain the string '>0.00</') then
   sed --in-place '\|>0.00</|d' $FILENAME 
fi

I suppose its the condition in the if statement that i'm not sure about. How would I go about stating "if all lines contain the above mentioned string"? I dont necessarily have to use sed, I have used awk in the past, but I am most comfortable with sed.... Any input or pointers in the right direction would be most appreciated. Thanks

Answer 1

grep -vq ">0.00<" $FILENAME || sed -i '\|>0.00<|d' $FILENAME

仅在所有行中包含0.00的文件中执行第二个命令。