正则表达式与浮点值不匹配

Question

I am trying to write a regular expression for these 2 lines of String

txt="[0, 0, 1.8, 1.0] value = 9.99999986991104E14";
txt="[0, 0, 1, 1] value = 9.99999986991104E14";

String re1=".*?";   // Non-greedy match on filler
String re2="\\d+";  // Uninteresting: int
String re3=".*?";   // Non-greedy match on filler
String re4="\\d+";  // Uninteresting: int
/*
* x 3rd value
*/
String re5=".*?";   // Non-greedy match on filler
String re6="(\\d+)";    // Integer Number 1
/*
* y 4 th value
*/
String re7=".*?";   // Non-greedy match on filler
String re8="(\\d+)";    // Integer Number 2
/*
* value
*/
String re9=".*?";   // Non-greedy match on filler
String re10="([+-]?\\d*\\.\\d+)(?![-+0-9\\.])"; // Float 1
String re11="((?:[a-z][a-z]*[0-9]+[a-z0-9]*))"; // Alphanum 1

Pattern p = Pattern.compile(re1+re2+re3+re4+re5+re6+re7+re8+re9+re10+re11,Pattern.CASE_INSENSITIVE | Pattern.DOTALL);
Matcher m = p.matcher(txt);

if (m.find())
{
    String x = m.group(1);
    String y = m.group(2);
    String value = m.group(3)+m.group(4);
    System.out.print("x "+x.toString()+" y "+y.toString()+" value"+value.toString()+"\n");
}

These regular expressions give me the the following result

case 1: x 1 y 8 value9.99999986991104E14
Case 2: x 1 y 1 value9.99999986991104E14

However, I had expected the results to be (case 1)

 Case 1: x 1.8 y 1.0 value9.99999986991104E14
 Case 2: x 1 y 1 value9.99999986991104E14

for x,y and value. I need to match both the integer and the float value.

Am I doing anything wrong with my regular expression?

Answer 1

Looking at the values for re6 and re8 , you are only looking at non decimal values (the dot is not included).

I suggest including the dot with the following changes

String re6 = "([.\\d]+)";

and

String re8 = "([.\\d]+)";

Edit for addition on the "value" part:

For the last Group, where you are trying to get number string, I would do it like this:

String re10 = "value ="; // Searching for fixed String value
String re11 = "[ ]*"; // Looking for whitespaces
String re12 = "([.E\\d]+)";// Looking for A String containing: Numbers/Dots/Letter-E at with at least one match

One Group to match both cases: Including E or not, Containing dot or not. - Since the value String is fixed, I included it in the regex.