Mongo DB 查询问题

Question

I am beginner in Mongo DB. I wrote the query see below for your further reference.

My Query is

$result =  $this->likes->find(array("post_id" => $post_id));

In that my table name is "likes" having the field name post_id , I am passing the $post_id (its my dynamic value example $post_id= "55b86fb60fdd9419128b4567" ).

But I cannot get my expected result from the below query, if I pass the $post_id is static means I got it my desired result.

Thanks advance for your help

Answer 1

You are attempting to use a string to match a MongoId . Keep in mind that these are two different datatypes. This is there in documentation

You should query like following:

$result =  $this->likes->find(array("post_id" => new MongoId($post_id)));

As explained in doc , You can print query result by using -

foreach ($result as $doc) {
  var_dump($doc);
}

Answer 2

请尝试以下操作：

$result =  $this->likes->find(array("post_id" => new MongoId($post_id)));

Answer 3

Try This:

function connection($tableName){        
    // Connect to Mongo
    //$this->connection = new MongoClient('localhost:27017'); //for linux
    $this->connection = new Mongo('localhost:27017'); // for window

    // Select a database
    $this->db = $this->connection->databaseName;

    // Select a collection
    $this->posts = $this->db->$tableName;
}

$this->connection('likes'); // likes is collection name
$id= "55b86fb60fdd9419128b4567";
$members = $this->posts->find(array("post_id" => $id));

Answer 4

Try this:

$result = $this->likes->find(array("post_id" => new\\ MongoId($post_id)));