[英]Sed replace variable in double quotes
I've created a bash script that takes a parameter. 我创建了一个带参数的bash脚本。 I want to pass that parameter to sed to replace an existing string with another which is composed of the variable:
我想将该参数传递给sed以将现有字符串替换为由变量组成的另一个字符串:
variable=$1
echo $variable
sed -i -e 's/name="master"/name="$variable"/g' test
The problem is that the script is not replacing $variable with the parameter, it's just replacing the string with "$variable": 问题是脚本没有用参数替换$ variable,它只是用“$ variable”替换字符串:
<host name=""$variable"" xmlns="urn:jboss:domain:3:0:>
How can I replace a string in quotes with the variable? 如何用变量替换引号中的字符串?
Variable expansion does not happen within single quotes. 单引号内不会发生变量扩展。 Do it in double quotes:
用双引号做:
sed -i -e 's/name="master"/name="'"$variable"'"/g' test
像他一样改变你的代码,
sed -i -e 's/name="master"/name="'"$variable"'"/g' test
just do like this: 就像这样:
var=apple
sed -i "s/pineapple/$"
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