Jenkins Job的Cron表达式

Question

I want to execute a job in Jenkins at 1.00 am on first Monday of every month.

00 01 1-7 * 1

Is this correct? Though i verified it using below link. Still not very sure.

test link

Answer 1

You are completely correct. If you would like, you can remove your leading zeroes from your first two numbers like this:

0 1 1-7 * 1 test.sh

You can read all about cron syntax here . To the best of my knowledge, Jenkins uses cron style formats but simply enhances it capabilities.