如何使用datediff函数显示日，时，分和秒

Question

I have a record:

Depart_dt               Arrived_dt 
10/1/2013 6:15:00 AM    10/1/2013 7:25:00 AM

Based on my calculation, it is 0 day, one hour, and 10 minutes between the arrived_dt and Depart_dt . How do I show the result like below:

Day   Hour  Minute  Second
0     1     10      0

Answer 1

You can use modulus division on the output of the DATEDIFF() function for this:

SELECT DATEDIFF(second,Depart_dt,Arrived_Dt)/(60*60*24) AS Day
      ,DATEDIFF(second,Depart_dt,Arrived_Dt)/(60*60)%24 AS Hour
      ,DATEDIFF(second,Depart_dt,Arrived_Dt)/(60)%60 AS Minute
      ,DATEDIFF(second,Depart_dt,Arrived_Dt)%60 AS Second
FROM Table1

Demo: SQL Fiddle

Answer 2

select 
datediff(second,depart_dt, arrived_dt)/86400 as Day,
datediff(second,depart_dt, arrived_dt)/3600%24 as Hour,
datediff(second,depart_dt, arrived_dt)/60%60 as Minute,
datediff(second,depart_dt, arrived_dt)%60 as Second
from yourtable

Converting days, hours and minutes into seconds for accuracy.

SQL Fiddle: http://sqlfiddle.com/#!6/c6c63/1