使用gcc时，如何使用由Intel编译器编译的库？
[英]How can I use libraries which were compiled by Intel compiler, when I'm using gcc?
问题描述
I'm running on Linux and I got a library (.a) which was compiled by Intel compiler. 
我在Linux上运行，并且有一个由英特尔编译器编译的库（.a）。
I'm trying to link against this static library (I'm using g++) and getting link error: 我正在尝试链接到此静态库（我正在使用g ++），并遇到链接错误：
undefined reference to intel_fast_memcpy
I requested to get the library as a shared library (.so) which was compiled by intel compiler too, and I got the same error. 我请求将该库作为共享库（.so），该库也由intel编译器进行了编译，但出现了同样的错误。
How can I use libraries which were compiled by Intel compiler, when I'm using gcc? 使用gcc时，如何使用由Intel编译器编译的库？
1 个解决方案
解决方案1
1 2015-08-02 14:49:33
As far as I know, there is no way to link C++ client code against C++ libraries built with different compiler (even same compiler name but different versions don't work). 据我所知，无法将C ++客户端代码与使用不同编译器构建的C ++库链接（即使相同的编译器名称，但不同的版本也不起作用）。 C++ -linkage is not stanrardised. 没有建立C ++链接。
However, C-linkage is. 但是，C链接是。 If you wrap a library to export the symbols as C, (external "C"{ } - block in your code) you could use these libraries with any compiler, and even not only with C/C++; 如果包装一个库以将符号导出为C（外部“ C” {}-代码中的块），则可以将这些库与任何编译器一起使用，甚至不仅限于C / C ++。 For doing this, the wrapper-lib should be built with intel-compiler in your case. 为此，在您的情况下，应该使用intel-compiler构建wrapper-lib。
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