为什么字符数组在Java中接受整数值？

Question

Of course I'm a beginner for Java, previously I learned C. Please take a look on the following code segments.

char Character;
int Number = 27;
Character = Number;
System.out.println(Character);

The above code cannot be compiled as an error stated as “Loss of Information”

Whereas the following code...

char Character = ‘F’;
int Number;
Number = Character;
System.out.println(Number);`

The above code can be compiled but the output is “70”... not as “F”

Also take a look on the following code...

char [] arrayCh = new char [3];
arrayCh [0] = 27;
System.out.println(arrayCh[0]);

The above code can be compiled however it also gives an unfamiliar symbol...

I know the issues regarding the ASCII Values and the memory taking as 'char' takes 16 Bits, 'int' takes 32 Bits. Therefore an integer value couldn't be assigned in to a character variable whereas a character value can be assigned in to an integer variable as "ASCII" value.

My question is... why a 'char' array accepts 'int' values..? Could anyone explain?

Answer 1

A char is a 2-bytes long, unsigned integer. 27 is an integer literal that is in the range of a char, so the compiler accepts to let you assign it to a char.

'F' is a character literal that represents the character F, which has the decimal value 70 in the unicode standard. So, assigning 'F' to an integer is the same thing as assigning 70.