如何在C ++中创建类型安全的int-枚举？

Question

I need to create many classes that are somewhere between integer and enum. Ie have the arithmetics of integer but also are not implicitly converted to int.

Answer 1

Have a look at the answer to this question - BOOST_STRONG_TYPEDEF did exactly what I wanted.

// macro used to implement a strong typedef.  strong typedef
// guarentees that two types are distinguised even though the
// share the same underlying implementation.  typedef does not create
// a new type.  BOOST_STRONG_TYPEDEF(T, D) creates a new type named D
// that operates as a type T.

Answer 2

一种可能性是使用:: GetValue（）方法创建一个类，该类的“枚举”定义为该类的不变成员，并且您需要使用重载的数学运算才能使用GetValue（）进行相关的数学运算。