如何使用Javascript / jQuery将长数字字符串值转换为数值

Question

User is allowed to insert up to 25 value in textbox .

i.e. 1234567890123456789012345

On change event of textbox I need to convert that same into numeric value to perform numeric operations and then after need to display same entered value with thousand separator along with 2 decimal places.

I tried the following code:

1. Number($('#textbox1').val()).toFixed(2).replace(/\\B(?=(\\d{3})+(?!\\d))/g, ",")
2. parseInt($('#textbox1').val(), 10).toFixed(2).replace(/\\B(?=(\\d{3})+(?!\\d))/g, ",")

Both gives me following output

1.2,345,679,801,234,568e+21

expected output:-

1,234,567,890,123,456,789,012,345.00

Answer 1

Try using autoNumeric js. Find it here

Answer 2

something like this work for you? I found it on the internet...

function addCommas(nStr) {
  nStr += '';
  x = nStr.split('.');
  x1 = x[0];
  x2 = x.length > 1 ? '.' + x[1] : '';
  var rgx = /(\d+)(\d{3})/;
  while (rgx.test(x1)) {
    x1 = x1.replace(rgx, '$1' + ',' + '$2');
  }
  return x1 + x2 + '.00';
}

Answer 3

for the numeric point of view, still i could not get any solution at JavaScript, so I have posted the value to server side and get JSon result.

But for the display purpose I have did finally :

function ChangeAmountFormat(target) {
var $this = $(target);
var num = $this.val().replace(/,/g, '').replace(/(\s)/g, '');
var decimalPointDeleted = '';

if (lastValue.length > 0 && lastValue.indexOf('.') > 0 && num.indexOf('.') < 0) {
    decimalPointDeleted = 'y';
}

if (num.indexOf('.') >= 0) {
    var numSplitValues = num.split('.');
    num = numSplitValues[0].toString().replace(/\B(?=(\d{3})+(?!\d))/g, ",");
    num += (num.length > 0 ? ('.' + numSplitValues[1]) : '');
}
else {
    if (decimalPointDeleted == 'y' && num.toString().substring((num.length - 2), num.length) == '00') {
        var tempNum = num.toString().substring(0, (num.length - 2));
        num = tempNum + '.' + num.toString().substring((num.length - 2), num.length);
    }
    else {
        num = num + (num.length > 0 ? '.00' : '');
    }

    num = num.replace(/\B(?=(\d{3})+(?!\d))/g, ",");
}

$this.val(num);
}

here, some more things also handles. Kindly ignore.