[英]Parse childs in XML python
I have a XML code like: 我有一个类似的XML代码:
<?xml version='1.0' encoding="UTF-8"?>
<coureurs>
<coureur>
<nom>Patrick</nom><hair>Inexistants</hair>
</coureur>
</coureurs>
And i want to print that: 我想打印:
Patrick inexistents
Etc...
For now my code is :
from lxml import etree
tree = etree.parse(file.xml)
for coureur in tree.xpath("/coureurs/coureur/nom"):
print(user.text)
but it returns blank, when i do: for user in tree.xpath("/coureurs/coureur/hair"): it only returns hair. 但是,当我这样做时,它返回空白:对于tree.xpath(“ / coureurs / coureur / hair”)中的用户:它仅返回头发。 what should i do? 我该怎么办?
I am still not able to reproduce the issue with the xml and code you provided. 我仍然无法通过您提供的xml和代码重现该问题。 But seems like you have left out a lot of xml , and most probably the XPATH
may not be working for you if coureurs
is not the direct root of the xml (or its direct child) . 但是似乎您已经遗漏了很多xml,并且如果coureurs
不是xml(或其直接子级)的直接根,则XPATH
可能对您coureurs
。
In such cases, you can use the following XPATH to get each coureur
node in the xml (that is the child of a coureurs
node) - 在这种情况下,您可以使用以下XPATH来获取xml中的每个coureur
节点(这是coureurs
节点的子节点)-
//coureurs/coureur
This would give you all <coureur>
tag elements from the xml , and then you ca iterate over that to print it's child's text . 这将为您提供xml中的所有<coureur>
标记元素,然后对其进行迭代以打印其子文本。 Example Code - 示例代码-
for user in tree.xpath('//coureurs/coureur'):
for child in user:
print(child.text,end=" ")
print()
Example/Demo - 示例/演示-
In [26]: s = """<?xml version='1.0' encoding="UTF-8"?>
....: <coureurs>
....: <coureur>
....: <nom>Patrick</nom><hair>Inexistants</hair>
....: </coureur>
....: </coureurs>"""
In [28]: tree = etree.fromstring(s.encode())
In [35]: for user in tree.xpath('//coureurs/coureur'):
....: for child in user:
....: print(child.text,end=" ")
....: print()
....:
Patrick Inexistants
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