Pycharm没有显示`PyQt5`程序的错误信息（例如`TypeError`）

Question

In Pycharm 4.5.2, if I had an error in PyQt5 slots, when the slots was called, Pycharm only shows Process finished with exit code 1 , but not where and why the error happends. This doesn't happen when the error is in __init__ .
It makes it very difficult to debug. How do I fix this?

This widget is generated by Qt Designer

For example, if I wrote button.setText('a'+1) when clicked on the button:

# -*- coding: utf-8 -*-

import sys
from PyQt5 import Qt
from test import Ui_Form

Application = Qt.QApplication(sys.argv)

class myWidget(Qt.QWidget):
    def __init__(self):
        super(myWidget, self).__init__()
        self.main = Ui_Form()
        self.main.setupUi(self)
        # self.main.pushButton.setText('a'+1)
        # prints `TypeError: Can't convert 'int' object to str implicitly ` normally

        self.show()

        self.main.pushButton.clicked.connect(self.show_error)

    def show_error(self):
        self.main.pushButton.setText('a'+1)
        # only print "Process finished with exit code 1" when clicked on the button, and crash.


my_Qt_Program = myWidget()
my_Qt_Program.show()
sys.exit(Application.exec_())

It works fine in windows console:

test.py(generated by Qt Designer):

# -*- coding: utf-8 -*-

# Form implementation generated from reading ui file 'test.ui'
#
# Created by: PyQt5 UI code generator 5.5
#
# WARNING! All changes made in this file will be lost!

from PyQt5 import QtCore, QtGui, QtWidgets

class Ui_Form(object):
    def setupUi(self, Form):
        Form.setObjectName("Form")
        Form.resize(115, 58)
        self.verticalLayout = QtWidgets.QVBoxLayout(Form)
        self.verticalLayout.setObjectName("verticalLayout")
        self.pushButton = QtWidgets.QPushButton(Form)
        self.pushButton.setObjectName("pushButton")
        self.verticalLayout.addWidget(self.pushButton)

        self.retranslateUi(Form)
        QtCore.QMetaObject.connectSlotsByName(Form)

    def retranslateUi(self, Form):
        _translate = QtCore.QCoreApplication.translate
        Form.setWindowTitle(_translate("Form", "Form"))
        self.pushButton.setText(_translate("Form", "Show \'a\' +1"))

Answer 1

Perhaps not exactly what you want but this works for me:

import logging

def main():
    x = 1/0

if __name__ == '__main__':
    logging.basicConfig(level='INFO')
    main()

Edit: The above mention method works if you got a single file but it doesnt fix the root of the problem A better anwser can be found here PyQt: No error msg (traceback) on exit

Answer 2

As has been pointed out in the comments and indeed suggested on this pycharm thread :

In your run configuration, enable the option Emulate terminal in output console . You can find this in the Execution section.

Running your example

On my machine (Windows 10, PyCharm Professional 2018.3.1) this changed the behaviour when clicking the show 'a' + 1 button from exiting with exit code ( -1073740791 (0xC0000409) ) to showing

Traceback (most recent call last):
  File "path/to/file/so.py", line 25, in show_error
    self.main.pushButton.setText('a' + 1)
TypeError: can only concatenate str (not "int") to str

In order to run your example I had to change

from PyQt5 import Qt

into

from PyQt5.QtWidgets import QApplication, QWidget

and change the Qt.Q... calls into Q... accordingly, but this might depend on my setup.