Javascript：将对象从一个数组移动到另一个数组：最佳方法？

Question

I have two arrays, called 'objects' and 'appliedObjects'. I'm trying to come up with an elegant way in Javascript and/or Angular to move objects from one array to another.

Initially I did something like this:

   $scope.remove = function () {
        angular.forEach($scope.appliedObjects, function (element, index) {
            if (element.selected) {
                element.selected = false;
                $scope.objects.push(element);
                $scope.appliedObjects.splice(index, 1);
            }
        });
    }

   $scope.add= function () {
        angular.forEach($scope.objects, function (element, index) {
            if (element.selected) {
                element.selected = false;
                $scope.appliedObjects.push(element);
                $scope.objects.splice(index, 1);
            }
        });
    }

But then I realized that when the value was removed from the looping array, and it would not add or remove every other item, since it went by index.

Then I tried using a temporary array to hold the list of items to be added or removed, and I started getting strange referential issues.

I'm starting to spin a bit on what the best solution to this problem would be...any help and/or guidance would much appreciated.

Answer 1

function moveElements(source, target, moveCheck) {
    for (var i = 0; i < source.length; i++) {
        var element = source[i];
        if (moveCheck(element)) {
            source.splice(i, 1);
            target.push(element);
            i--;
        }
    } 
}

function selectionMoveCheck(element) {
   if (element.selected) {
       element.selected = false;
       return true;
   }
}

$scope.remove = function () {
    moveElements($scope.appliedObjects, $scope.objects, selectionMoveCheck);
}

$scope.add = function () {
    moveElements($scope.objects, $scope.appliedObjects, selectionMoveCheck);
}

Answer 2

When a construct does too much automatically (like forEach, or even a for-loop, in this case), use a more primitive construct that allows you to say what should happen clearly, without need to work around the construct. Using a while loop, you can express what needs to happen without resorting to backing up or otherwise applying workarounds:

function moveSelected(src, dest)  {
    var i = 0;
    while ( i < src.length ) {
        var item = src[i];
        if (item.selected) {
            src.splice(i,1);
            dest.push(item);
        }
        else i++;
    }
}

Answer 3

If you wish to move simply whole array you could do:

appliedObjects = objects;
objects = []

Of course it won't work if they were parameters of a function! Otherwise I cannot see other way than copying in the loop, eg

while (objects.length) {
    appliedObjects.push(objects[0]);
    objects.splice(0,1);
}

or if you like short code :) :

while (objects.length) appliedObjects.push(objects.splice(0,1));

check fiddle http://jsfiddle.net/060ywajm/

Answer 4

You are altering the array while iterating on it, you will always miss some elements.

One way of doing it would be to use a third array to store the references of the objects that need to be removed from the array:

// "$scope.add" case
var objectsToRemove = [];

$scope.objects.forEach(function (value) {
  if (value.selected) {
    value.selected = false;
    $scope.appliedObjects.push(value);
    objectsToRemove.push(value);
  }
});

objectsToRemove.forEach(function (value) {
  $scope.objects.splice($scope.objects.indexOf(value), 1);
});

Answer 5

Now this maybe is not a fair answer, but if you notice you are doing alot of complicated object/array manipulations, you should really check out lodash or underscore library. then you could solve this with on liner:

//lodash remove function
appliedObjects.push.apply( appliedObjects, _.remove(objects, { 'selected': true}));

//or if you want to insert in the beginning of the list:
appliedObjects.splice(0, 0, _.remove(objects, { 'selected': true}));

Answer 6

This is a first pass at what I think will work for you. I'm in the process of making a test page so that I can test the accuracy of the work and will update the tweaked result, which hopefully there will not be.

EDIT: I ran it and it seems to do what you are wanting if I understand the problem correctly. There were a couple of syntax errors that I edited out.

Here's the plunk with the condensed, cleaned code http://plnkr.co/edit/K7XuMu?p=preview

HTML

<button ng-click="transferArrays(objects, appliedObjects)">Add</button>
<button ng-click="transferArrays(appliedObjects, objects)">Remove</button>

JS

$scope.transferArrays = function (arrayFrom, arrayTo) {
var selectedElements;
selectedElements = [];
angular.forEach(arrayFrom, function(element) {
  if (element.isSelected) {
    element.isSelected = false;
    selectedElements.push(element);
  }
});
angular.forEach(selectedElements, function(element) {
  arrayTo.push(arrayFrom.splice(
    arrayFrom.map(function(x) {
      return x.uniqueId;
    })
    .indexOf(element.uniqueId), 1));
});
};

Old code

$scope.remove = function () {
        var selectedElements;
        selectedElements = [];
        angular.forEach($scope.appliedObjects, function (element) {
            if (element.isSelected) {
                element.isSelected = false;
                selectedElements.push(element);
            }
        });
        angular.forEach(selectedElements, function (element) {
            $scope.objects.push($scope.appliedObjects.splice(
                $scope.appliedObjects.map(function  (x) { return x.uniqueId; })
                .indexOf(element.uniqueId), 1));
        });
    };

$scope.add = function () {
        var selectedElements;
        selectedElements = [];
        angular.forEach($scope.objects, function (element) {
            if (element.isSelected) {
                element.isSelected = false;
                selectedElements.push(element);
            }
        });
        angular.forEach(selectedElements, function (element) {
            $scope.appliedObjects.push($scope.objects.splice(
                $scope.objects.map(function  (x) { return x.uniqueId; })
                .indexOf(element.uniqueId), 1));
        });
    };

Answer 7

您可以多次使用此 oneliner 将需要从 arr1 移动到 arr2 的项目数量，只需准备检查功能

arr2.push(arr1.splice(arr1.findIndex(arr1El => check(arr1El)),1)[0])

Answer 8

You can use this to concat 2 arrays. let array3 = [...array1, ...array2];