如何在Python 3中将原始十六进制字节写入stdout？

Question

How do you get Python 3 to output raw hexadecimal byte? I want to output the hex 0xAA .

If I use print(0xAA) , I get the ASCII '170'.

Answer 1

print() takes unicode text and encodes that to an encoding suitable for your terminal.

If you want to write raw bytes, you'll have to write to sys.stdout.buffer to bypass the io.TextIOBase class and avoid the encoding step, and use a bytes() object to produce bytes from integers:

import sys

sys.stdout.buffer.write(bytes([0xAA]))

This won't include a newline (which is normally added when using print() ).

Answer 2

The solution was to first create a bytes object:

x = bytes.fromhex('AA')

And then output this to stdout using the buffered writer

sys.stdout.buffer.write(x)

Answer 3

You can also use the hex-byte escape sequence ("\\x") in a bytestring, specifying the sys.stdout.buffer.write() method:

$ python -c 'import sys; sys.stdout.buffer.write(b"\x74\x68\x65\x73\x65\x20\x61\x72\x65\x20\x72\x61\x77\x20\x62\x79\x74\x65\x73\x21\xde\xad\xbe\xef")'

will output on your terminal:

these are raw bytes!ޭ��%

and inspecting with xxd :

$ python -c 'import sys; sys.stdout.buffer.write(b"\x74\x68\x65\x73\x65\x20\x61\x72\x65\x20\x72\x61\x77\x20\x62\x79\x74\x65\x73\x21\xde\xad\xbe\xef")' | xxd
00000000: 7468 6573 6520 6172 6520 7261 7720 6279  these are raw by
00000010: 7465 7321 dead beef                      tes!....